How can I copy the last line in a text file to another text file - batch file

I'm running curl through a batch file and print the output to a text file. I want to copy the last line of this text file to another file so i'll have something like:

The first file:

  0  594M    0 1017k    0     0   813k      0  0:12:27  0:00:01  0:12:26  813k
  0  594M    0 2735k    0     0  1215k      0  0:08:20  0:00:02  0:08:18 1215k
  0  594M    0 5074k    0     0  1561k      0  0:06:29  0:00:03  0:06:26 1561k
  1  594M    1 6716k    0     0  1580k      0  0:06:25  0:00:04  0:06:21 1580k
  1  594M    1 8027k    0     0  1489k      0  0:06:48  0:00:05  0:06:43 1566k
  1  594M    1 8438k    0     0  1350k      0  0:07:30  0:00:06  0:07:24 1484k
  1  594M    1 8883k    0     0  1225k      0  0:08:16  0:00:07  0:08:09 1229k
  1  594M    1 9555k    0     0  1158k      0  0:08:45  0:00:08  0:08:37  896k

The second file:

 1  594M    1 9555k    0     0  1158k      0  0:08:45  0:00:08  0:08:37  896k

The batch file is:

curl -v -o NUL "http://...." 2>> file1.txt
timeout 10 /NOBREAK
copy /y file1.txt file1.tmp.txt 1>nul

setLocal EnableDelayedExpansion
    for /f "tokens=* delims=" %%a in (file1.tmp.txt) do (
    set var_file1=%%a  
    )
echo !var_file1!
echo !var_file1! > file2.txt

The problem is that the first echo line prints the last line but the second line copy the entire file1 to file2.

What should I change in order to copy only the last line of file1 to file2 ?

Thanks!